Question

in the given fig, ∆ABC is an equilateral triangle and ∆BDC is an isosceles right triangle right angled at D. find angle ABD

Answer 1

30 is the answer of this question iy hugTh Hu JDDJSBUDBEHZJDIDBEUSJ DKDS

Answer 2

Firstly i think you mean ∆ADC not ∆BDC as for BDC being right triangle the condition is technically next to impossible

Second considering∆ADB &∆CDB we have

AD=DC(isosceles triangle)

AB=BC(equilateral)

DB=DB(common)

So the triangles are congruent thus

AngleABD=angleCBD

& AngleABD+angleCBD=60°

Thus angle ABD=30°