In the given fig. ABCD is a parellelogram and L is the mid-point of DC. If area of ABCD =124cm2 then find area of triangle BCL.
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Answer:
31cm^2
Step-by-step explanation:
Ar(DBC) =1/2 ar(ABCD)
[triangle on the same base and between same parallels]
Ar(DBC) =62cm^2
Now
as L is the mid point of side DC
L is the median of triangle DBC
ar(BCL)=1/2 ar(DBC)
ar(BCL) =31cm^2
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