Question

In the given fig AC=AE, AB=AD and angle BAD= angle EAC. show that BC= DE​

Answer 1

Answer:

It is given that ∠BAD=∠EAC

∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]

∴∠BAC=∠DAE

In △BAC and △DAE

AB=AD (Given)

∠BAC=∠DAE (Proved above)

AC=AE (Given)

∴△BAC≅△DAE (By SAS congruence rule)

∴BC=DE (By CPCT)

Answer 2

Answer:

please give me 5 points

Step-by-step explanation:

this is right answer