Question

in the given fig AC =dc; cb =ce, show that ab=de

Answer 1

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Hola Mate! ❤❤

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This question is based on Euclids Geomentry

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Given,

AC = DC

CB = CE

To prove,

AB = DE

Proof,

AC = DC → 1 (given)

CB = CE → 2 (given)

From  → 1 and → 2 we get

AC + CB = DC + CE (If equals are added to equals the wholes are equals)

⇒ AB = DE

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Hope it Helps!

#BeBrainly

Answer 2

Answer:

Step-by-step explanation:

AC=AD

CB=CE

AC+CB=DC+CE

Since, if equals are added to equal, the sole is equal

AB=DE