In the given fig ad pallaral to bc if bd / ad = ad / dc prove that abc is aq right angled triangle
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In right triangles ADB & ADC, we have:
AB2 = AD2 +BD2 . . . . . . . . .1
AC2 = AD2+ DC2 . . . . . . . . 2
From 1 & 2,
AB2 + AC2 = 2AD2 + BD2 + DC2
= 2BD . CD + BD2 + CD2 [Given: AD*2 = BD . CD]
= (BD + CD)2 = BC2
Thus, in triangle ABC we have , AB2 + AC2 = BC2
Hence, triangle ABC is a right triangle right angled at A.
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