In the given fig, Angle ABC=70° and Angle ACB=30°. find Angle ADC Full Solution
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Answer:
∠ACB = 55° if O is the center of the circle and Angle ABD =35 and angle BAC =70
Step-by-step explanation:
∠ADB = ∠ACB as both angles from same chord on same side
O lies on BD
Hence BD is Diameter
and∠DAB = 90°
in Δ ABD
∠DAB + ∠ADB + ∠ABD = 180°
=> 90° + ∠ADB + 35° = 180°
=> ∠ADB = 55°
∠ADB = ∠ACB
=> ∠ACB = 55° . please mark me as brainlist
Step-by-step explanation:
please mark me as brainlist
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