Question

In the given fig angle ABD =54°and angle BCD =43°,calculate i) angle ACB ii) BCD iii) BDA

Answer 1

∠ACB =  97° , ∠BAD = 43° , ∠BDA =  83°

Step-by-step explanation:

∠ACD = ∠ABD   ( angle by same chord AD)

=> ∠ACD =  54°

∠BAD = ∠BCD   ( angle by same chord BD)

=> ∠BAD = 43°

∠ACB = 43° + 54° = 97°

∠BDA = 180° - 97°  ( sum of opposite angles of cyclic quadrilateral = 180°)

=> ∠BDA =  83°

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