Question

: In the given fig. angle ACD = 110°,angle BAC=45°. Find the value of x.

Answer 1

Step-by-step explanation:

let angle ACB be angle 1

angle 1 + angle ACD = 180 ( linear pair )

angle 1 + 110 = 180

angle 1 = 180 - 110

angle 1 = 70

angle 1 + angle CAB + angle x = 180

70 + 45 + angle x = 180

115 + angle x = 180

angle x = 180 - 115

angle x = 65

OR

angle CAB + angle x = 110 (exterior angle property )

45 + angle x = 110

angle x = 110 - 45

angle x = 65

Answer 2

$\huge \mathfrak \red{AnswEr}$

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• $= > x = 65$

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❥︎$\huge\underline\bold\pink{Given}$

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• A = 45°
• B = x
• ACB = y
• ACD = 110°

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❥︎$\huge\underline\bold\blue{To Find}$

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• x = ?
• y = ?

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❥︎$\huge\underline\bold\green{SoluTion}$

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ACB + ACD = 180°.....linear pair

$= > y + 110 = 180$

$= > y = 180 - 110$

$= > y = 70$

hence,

in triangle ABC ,

A + B + C = 180°......angles of triangle

$= > 45 + x + 70 = 180$

$= > x + 115 = 180$

$= > x = 180 - 115$

$= > x = 65$

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