Question

In the given fig. AO = BO & CO = DO. Prove that AC II DB & AC =DB.

Answer 1

Step-by-step explanation:

Here , AO = BO ( equal side )

/_AOC = /_BOD ( equal angle )

CO = DO ( equal side )

So, from SAS we have ∆AOC ~ ∆BOD

So that AC = BD

And /_OAC = /_OBD

and AOB is line

So , we get Z shape for intersection of 2 parallel lines.

So, AC || BD