In the given fig AOC = ACO and BOD = BDO prove that AC parallel DB .
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Solution:-
We have,
∠ AOC = ∠ ACO and ∠ BOD = ∠ BDO
But, ∠ AOC ∠ BOD (Vertically opposite angles)
∴ ∠ ACO = ∠ BOD and ∠ BOD = ∠ BDO
⇒ ∠ ACO = ∠ BDO
Thus AC and BD are two lines intersected by transversal CD such that ∠ ACO = ∠ BDO i.e. alternate angles are equal. Therefore AC II DB
We have,
∠ AOC = ∠ ACO and ∠ BOD = ∠ BDO
But, ∠ AOC ∠ BOD (Vertically opposite angles)
∴ ∠ ACO = ∠ BOD and ∠ BOD = ∠ BDO
⇒ ∠ ACO = ∠ BDO
Thus AC and BD are two lines intersected by transversal CD such that ∠ ACO = ∠ BDO i.e. alternate angles are equal. Therefore AC II DB
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