Question

In the given fig.,AP=10cm.The perimetre of quadrilateral APOQ is 26cm.Then radius of the circle is -----------

Answer 1

is equal to 10 then a q is equal to 10
hope this may help you

Answer 2

Answer:

The radius of the circle is 3 cm.

Step-by-step explanation:

Given :  AP=10cm. The perimeter of quadrilateral APOQ is 26cm.

To find : The radius of the circle?

Solution : In the given figure,

AP= 10 cm is the tangent from the circle.

By the theorem of two-tangent theorem,

If two tangent segments are drawn from the same external point, then the segments are equal.

i.e, AP=AQ = 10 cm

In the circle, OP and OQ are the radius of the circle.

So, OP=OQ=x (Let)

We have given,

The perimeter of quadrilateral APOQ is 26cm.

i.e, AP+AQ+OP+OQ= 26

Substituting the values,

2(AP)+2(OP)= 26

2(10)+2(x)= 26

2(x)= 26-20

x= 6/2

x=3

Therefore, The radius of the circle is 3 cm.