In the given fig. AP is tangent to circle at A. Find the value of X?
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AP is perpendicular to AO { according to the therom that angle between tangent and radius is 90 degree}
so by Pythagoras therom ,
(x+2)^2 =(x+1)^2 + 3^2
x^2+4x+4 = x^2+2x+1+9
{x^2 will get canceled }
4x+4=2x+10
4x-2x=10-4
2x=6
x=3.
the sides are : -
AP=(x+1)
=4
OP = (X+2)
= 5
hope it helped !!!
if it helped , pls mark it as brainliest ans
so by Pythagoras therom ,
(x+2)^2 =(x+1)^2 + 3^2
x^2+4x+4 = x^2+2x+1+9
{x^2 will get canceled }
4x+4=2x+10
4x-2x=10-4
2x=6
x=3.
the sides are : -
AP=(x+1)
=4
OP = (X+2)
= 5
hope it helped !!!
if it helped , pls mark it as brainliest ans
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