Question

In the given fig, APB and CQD are semi circles of diameter 7 cm each, while ARC and BSD are semicircles of diameter 14 cm each. Find the perimeter of the shaded region. (Use π = 22/7)

Answer 1

Given:
Diameter of semicircle APB & CQD = 7 cm
Diameter of semicircle ARC & BSD = 14 cm

From the given figure We have,

FOR SEMICIRCLE ARC:
Diameter AC =14 cm
Radius for semicircle ARC = 14/2= 7 cm

FOR SEMICIRCLE APB
Diameter AB=7 cm
Radius for semicircle AB = 7/2 cm

FOR SEMICIRCLE BSD
Diameter BD =14 cm
Radius for semicircle BD = 14/2= 7 cm

FOR SEMICIRCLE CQD
Diameter CD=7 cm
Radius for semicircle CD = 7/2 cm

PERIMETER OF CIRCLE = πr

Perimeter of the shaded region= Perimeters of semicircle (ARC + APB + BSD + CQD)

Perimeter of the shaded region= π×7 + π ×7/2 +π×7 + π ×7/2
= π(7+7/2+7/7/2)
= π(14+ 7/2+7/2) = π( 14 +7)
= 22/7 × 21
= 22 × 3 = 66 cm

Hence, the Perimeter of the shaded region is 66 cm.

HOPE THIS WILL HELP YOU...

Answer 2

Step-by-step explanation:

I hope it will helps you