In the given fig , BD=DC &
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As BD=DC ...... (given)
⇒∠DBC=∠DCB=30
∘
⇒∠BDC=120
∘
As ABCD is a cyclic quadrilateral ; ∠BAC+∠BDC=180
∘
⇒∠BAC=180
∘
−120
∘
=60
∘
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