In the given fig, BD perpendicular to AC, angle DCB = 30 degrees and angle EAC = 50 degree. Find the values of x and y.
URGENT!!!!
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ajay2:
which figure is it?
The triangle one
Is y abc or dbc
DBC
please give a clear pic
My room's got a dim light
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Answered by
9
X= 100 degree. As an aec by angle sum property, aec=80 degree and then by lpa x=100degree
Ok
In triangle AEC by angle sum property, AEC=80 degree and then by linear pair axiom, x=100degree
And y?
For y, take triangle DBC and here simply by angle sum property, y=60degree
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Answered by
32
Call intersection point of AE and BD as F.
In triangle AFD, angle AFD = 180 - (FAD - FDA) = 180 - ( 90 - 50 ) = 40 deg
At point F, angle AFD = BFE = 40 deg
Angle x can be found in two ways. but we do one way.
in triangle EAC, angle AEC = 180 - angle EAC - angle ECA
= 180 - 50 - 30 = 100 deg
So angle AEB = x = 180 - 100 deg = 80 deg
Now in triangle BFE, x + y + 40 = 180
as x = 80, 80 + y + 40 = 180
y = 60
In triangle AFD, angle AFD = 180 - (FAD - FDA) = 180 - ( 90 - 50 ) = 40 deg
At point F, angle AFD = BFE = 40 deg
Angle x can be found in two ways. but we do one way.
in triangle EAC, angle AEC = 180 - angle EAC - angle ECA
= 180 - 50 - 30 = 100 deg
So angle AEB = x = 180 - 100 deg = 80 deg
Now in triangle BFE, x + y + 40 = 180
as x = 80, 80 + y + 40 = 180
y = 60
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