in the given fig, D and Eare the midpoints of AB and AC respectively ifDE=4cm, then the value BC is
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In △ABC, DE∥BC
⇒ ∠B=∠D [ Corresponding angles ]
⇒ ∠C=∠E [ Corresponding angles ]
⇒ ∠A=∠A [ Common angle]
∴ 4△ABC∼△ADE [ By AAA criteria ]
(i) area(△ADE)area(△ABC)=(DEBC)2 [ Ratio of areas of two similar triangles is equal the ratio of squares of their corresponding sides. ]
∴ 16area(△ABC)=(46)2
∴ area(△ABC)=1636×16
∴ area(△ABC)=36cm2
(ii) area(△ADE)area(△ABC)=(DEBC)2 [ Ratio of areas of two similar triangles is equal the ratio of squares of their corresponding sides. ]
∴ 25area(△ABC)=(48)2
∴ area(△ABC)=16
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