Question

In the given fig. DE || BC, ∟ADE =70° and ∟BAC=50°, then angle

∟BCA = ______​

Answer 1

Step-by-step explanation:

In Triangle ADE ( By Angle Sum Property)

Angle ADE + Angle BAC + Angle BCA = 180°

70° + 50° + Angle BCA = 180°

120° + Angle BCA = 180°

Angle BCA = 180°- 120°

Angle BCA = 60°