In the given fig., if AB ll CD, then find the value of x
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The answer of this question is x=70°
Solution is in image attached.
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Given :-
- Angle EAB = 40°
- Angle ECD = 110°
- Angle AEC = x °
- AB|| CD .
To Find :-
- Value of x.
Solution :-
[Construction ]
→ Extend EC to intersect the line AB at P point.
Now we have a Triangle EAP.
→ Angle EPB = Angle ECD [ Corresponding angles between two parallel lines ie AB and CD .]
→ Angle EPB = 110°
Angle EPB is the exterior angle of triangle EAP .
By exterior angle sum property
→ Angle EAP + Angle AEP = Angle EPB
→ 40° + x° = 110°
→ x = 110 - 40
→ X = 70°
So the value of x is 70 degree.
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