In the given fig.if AD⊥BC prove that AB²+CD²=BD²+AC²
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AD² = BD²-AB²(by pathagrous theorem)
similar, AD²=CD²-AC²
BD²-AB²=DC²-AC² ( because AD² )
we get
-AB²-CD²=BD²-AC²(multiple - )
AB²+CD²=BD²+AC²
hence proved
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