Question

In the given fig. if radius of circle is 3cm. Find the perimeter of ∆ABC.​

Answer 1

Answer

Cont:- join center to all the radius forming

By phythagoras:-

(3✓5)^2=(3)^2 +BF^2

45 = 9 + BF^2

BF = 6 cm

DB = BF ( TANGENT TO CIRCLE)

:- DB = 6 cm

BY PHYTAGORAS :-

similarly CD = 6cm

CD=CE=6cm ( TANGENT TO CIRCLE)

As we know that the side which is oppt to tangent it is equal in two times

Therefore :- AO=2OD

i.e. AO=6✓5 cm

By phythagoras :-.

(6√5)^2= (3)^2 + AE^2

180 = 9 + AE^2

171 = AE^2

AE =13.07 ( approx)

i.e AE =13 cm

AE=AF=13 cm. (Tangent to circle)

Perimeter = 13+6+13+6+6+6

=50 cm ( approx)

Thanks have a nice day