In the given fig. Lines AB and CD intersect at 0. If LAOC+LBOE= 70° and LBOD= 40°
find LBOE, Reflex LCOE, LAOD and LAOC.
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In the given figure, lines AB and CD intersect at O.If ∠AOC+∠BOE=70
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and ∠BOD=40
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find ∠BOE and reflex of ∠COE
Given:∠BOD=40
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Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)
∠AOC=40
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Also,∠AOC+∠BOE=70
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⇒∠BOE=70
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−∠AOC=70
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−40
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=30
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We need to find reflex∠COE
Reflex∠COE=360
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−∠COE
Now, ∠AOC+∠COE+∠BOE=180
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⇒∠COE+(∠AOC+∠BOE)=180
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⇒∠COE+(40
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+30
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)=180
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⇒∠COE=180
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−70
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=110
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Reflex∠COE=360
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−110
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=250
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