In the given fig.< = 690 , < = 310 , find < BDC.
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Answer:
∠BDC=80°
Step-by-step explanation:
In △ABC
∠BAC+∠ABC+∠ACB=180° (Angle sum property)
∠BAC+69° + 31° = 180°
∠BAC = 180° - 100° = 80°
For segment BADCB,
VBDC and ∠BAC are angles in the same segment. So, they must be equal
∴ ∠BDC=∠BAC (Angles in the same segment are equal)
∠BDC=80°
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