Question

in the given fig o is the centre of a circle find x or angle aob

Answer 1

hey....

1. In triangle AOC

OA = OC..... (radius of circle)

angleOAC = angle = OCA = 40.

2.In triangle BOC

OB = OC......(radius of circle)

angleOBC = angleOCB = 30.

3.angle OCA + angleOCB = angleACB

= 40 + 30 = 70 degree.

4.angleAXB = 2 × angleACB... (angle suspended theorem)

angleAXB = 2 × 70

= 140 degree.

( x = 140...)

Answer 2

I have written the answer on two pages namely 1st and 2nd I think my answer is correct