in the given fig OA=5cm,AB=8cm find the distance of chord from centre o
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OA=5
AB=8
LET" C" BE THE MIDPOINT OF AB
THEN AC=4 & BC=4
By Pythagoras theorem
(H)^2=(P)^2+(B)^2
(5)^2=(P)^2+(4)^2
25=P^2+16
P^2=25-16
P^2=9
P=3
distance of chord is 3cm
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