Question

In the given fig P and Q are mid points of AB and AC and ∠A=55°,What is the value of x and CR ?

Answer 1

Answer:

X=125° ,CR=5cm

Step-by-step explanation:

In ∆AQP AND ∆RWC,

AQ= QC,AP=BP Given HENCE BP=CR=5cm

angle APQ=angle RQC (vertically opposite angle )

Therefore,∆AQP concurrent to ∆RQC.

angle PBC+angle RCB =180°

angle RCB =180°- angle PBC

angle RCB = 180°-55°=125°

X=125°

Answer 2

Answer:

x=125°,CR=5cm

Step-by-step explanation:

In ∆AQP and ∆RWC,

AQ=QC,AD=BPgiven hence

BP=CR =5cm

angle APQ =angle RQC (vertically opposite angle)

Therefore, ∆AQP concurrent to ∆RQC.

Angle PBC + angle RCB =180°

angle RCB =180°-55°=125°

x=125°