in the given fig. PA and PB are tangent to a circle with centre O if angle APB = (2x+3)° and angle AOB = ( 3x+7)° then find the angle x.
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<APB+<AOB×<OAB+<OBP=360
(2x+3)+(3x+7)+90+90=360
5x= 360-190
x=170÷5
x=34
(2x+3)+(3x+7)+90+90=360
5x= 360-190
x=170÷5
x=34
Michelle15:
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