Question

in the given fig point p is the centre of the circle chord ab Chord cd chord ab and chord cd intersect at point M.P.T angle pAD =Angle CAB​

Answer 1

Answer:

Construction : Draw perpendicular from point to the chord CD and AB

To prove : AB=CD

Proof : In △MEP and △NEP

∠EMP=∠ENP=90

∘

∠AEP=∠DEP(Given)

EP=EP(common)

Thus, by AAS congruence rule, △MEP≅△NEP

So, MP=NP(CPCT)

We know that chords equidistant from the centre are equal to each other.

Hence , AB=CD