Question

In the given fig. PQ = 24cm ,QR = 26cm, ∠ PAR = 90°, PA = 6cm and AR = 8cm, find ∠ QPR.

Answer 1

PYTHAGORAS THEOREM: In a right angle triangle the square of the hypotenuse is equal to the sum of the square of the other two sides.

CONVERSE OF PYTHAGORAS THEOREM: In a triangle if square of one side is equal to the sum of the squares of the other two sides then the angle opposite to first side is a right angle.

SOLUTION:
Given :
PQ = 24cm  ,QR = 26cm,  ∠ PAR = 90°,  PA = 6cm and AR  = 8cm

In ∆ PAR,
PR² = AR² + AP²

[By Pythagoras theorem]
PR² = 8² + 6²
PR² = 64 +36
PR² = 100
PR = √100

PR = 10 cm

In ∆ QPR
QR² = QP² + PR²
26² = 24² + 10²
26² = 576 + 100
26² = 676
676 = 676

∠QPR  = 90°

[By Converse of Pythagoras theorem]

Hence the value of ∠QPR  = 90°.

HOPE THIS WILL HELP YOU....

Answer 2

Answer:

do remember the answer is correct mentioned above

triangle QPR is right angle.