in the given fig. PQR is the tangent to a circle at Q whose centre is O.AB is a chord parallel to PR and Angle BOR =60*.find angle AQB
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Divyankasc:
Its angle BOR only na ? not BQR right ? Just rechecking
no ...its BOR
only
Class ?
class 10
:l I think it should be BQR that's why
Like this one http://m.meritnation.com/ask-answer/question/pqr-is-the-tangent-to-a-circle-at-q-whose-center-is-o-ab/math/3655894
no divya in question paper its given as BOR
I think if u have took it from learncbse m.the question maybe wrong m.I don't know sorry bye!
its ok....btw i took it from EAD....
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angle AQB = half of angle BOR
sub the values and get the answer by intercepted angle theorem
sub the values and get the answer by intercepted angle theorem
why AQB is half BOR....can u state the reason please
construction of BOR
refer chap circle of std X of CBSE Board
Ull get it
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