Question

IN THE GIVEN FIG. PQRS IS A REATANGLE PQ= 11CM, PS= 60CM. THEN THE FIND THE VALUE OF AB=?​

Answer 1

Given :  PQRS IS A REATANGLE PQ= 11CM, PS= 60CM

To Find :  VALUE OF AB

Solution:

Let right top circle touching PS at M  &  SR at N

PB = PM    Equal Tangent

SM  = SN Equal Tangent

PS = PM + SM = 60

=> PB + SN  =  60

RS = RN + SN = 11

RN = RB

=> RB + SN = 11

PB + SN  =  60

RB + SN = 11

=> PB  - RB  = 49

Similarly we can Show that

  RA  -  PA  = 49

PA + AB - RB =  49      PB = PA + AB

RB + AB - PA  = 49      RA = RB + AB

Adding Both

2AB = 98

=> AB = 49

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