In the given fig., PS /SQ= PT/TR and ∠PST = ∠PRQ. Prove that PQR is an isosceles .
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Converse of basic proportionality theorem:
If a line divides any two sides of a triangle in the same ratio then the line must be parallel to the third side.
GIVEN:
PS /SQ= PT/TR & ∠PST = ∠PRQ.
We have,
PS /SQ= PT/TR
ST || QR
[By using the Converse of basic proportionality theorem]
∠PST = ∠PQR [corresponding angles]
∠PRQ = ∠PQR [ ∠PST = ∠PRQ]
PQ = PR
[Sides opposite to equal angles are equal]
Hence, ∆PQR is Isosceles .
HOPE THIS WILL HELP YOU...
If a line divides any two sides of a triangle in the same ratio then the line must be parallel to the third side.
GIVEN:
PS /SQ= PT/TR & ∠PST = ∠PRQ.
We have,
PS /SQ= PT/TR
ST || QR
[By using the Converse of basic proportionality theorem]
∠PST = ∠PQR [corresponding angles]
∠PRQ = ∠PQR [ ∠PST = ∠PRQ]
PQ = PR
[Sides opposite to equal angles are equal]
Hence, ∆PQR is Isosceles .
HOPE THIS WILL HELP YOU...
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