Question

In the given fig., PS /SQ= PT/TR and ∠PST = ∠PRQ. Prove that PQR is an isosceles .​

Answer 1

Answer:

Here, PS/SQ = PT/TR

By converse of BPT, ST // QR

Therefore, ∠PST = ∠PQT

As ∠PST = ∠PRQ,

=> ∠PQT = ∠PRQ

Hence, ∆PQR is an isosceles ∆.

More:

Perimeter of isoscleles triangle = 2a + b

Area = b/2√(a² - b²/4)

Answer 2

Answer:

Hope you get the correct answer.