Question

In the given Fig. QS is a tangent to the circle, OS=8 cm and OQ= 6 cm then the leng
Problem
a)
$\sqrt[]{28}$
b) 10 cm. c)20 cm. d) 14 cm
l​

Answer 1

using Pythagoras theorem

os^2=oq^2+Qs^2

os^2= 8^2+6^2

os^2= 64+36

os^2=100

os= 10

Answer 2

Step-by-step explanation:

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