in the given fig. ST II RQ, PS=3cm &SR = 4cm. find ratio of area of PRQ
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arPQR/arPST = ps²/sr²
= 9/16 so , ratio = 9:16 ans.
= 9/16 so , ratio = 9:16 ans.
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Area of triangle pst/area of triangle PRQ= (ps/pr) square = (3/7) square =9/49.
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