In the given fig. the radius of the circle is 5cm..Find the area of the shaded region
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Answer:
⇒ Here, r=5cm and θ=90
o
⇒ Area of sector OABO=
360
θ
πr
2
=
360
o
90
o
×3.14×(5)
2
∴ Area of sector OABO=
4
3.14×25
=19.62cm
2
⇒ Area of △AOB=
2
1
×AO×BO=
2
1
×5×5
∴ Area of △AOB= 2 25
=12.5cm ^2
∴ Area of minor segment made by the chord AB = Area of sector OABO - Area of △AOB
∴ Area of minor segment made by the chord AB =19.62−12.5=7.12cm
2
⇒ Area of circle =πr
2
=3.14×(5)
2
∴ Area of circle =78.5cm
2
⇒ Area of major segment made by chord AB = Area of a circle - Area of minor segment.
∴ Area of major segment made by chord AB=78.5−7.12=71.38cm
2
Step-by-step explanation:
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