Question

In the given figure 0 is the center of the circle. Find angle BAC

Answer 1

AN ANGLE SUBTENDED BY ANY ARC ON CENTRE OF CIRCLE IS TWICE TO THE SUBTENDED AT ANY OTHER POINT ON CIRCLE ,

by arc BD. angle BOD=2×angle BAD= 150° and angle BCD = ½ (angle BOD) = 75°, In ∆BOD,OB = OD

angle BOD= angle ODB and angle OBD + angle ODB + angle BOD = 180°

2 angle OBD =180-150

angle OBD = 15°

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