in the given figure 0 is the centre of the circle and PA,PB are tangents to the circle .if angle APB=60degree,find angle ACB
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Angle ACB=60*
As angle PAO and angle PAO =90*
So angle AOB=120*
And angle AOB is twice of angle ACB . So angle ACB =60
As angle PAO and angle PAO =90*
So angle AOB=120*
And angle AOB is twice of angle ACB . So angle ACB =60
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