In the given figure 1 II m is cut by a transversalt. If angel1 = 65°, find all other
angles in the figure.
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pls attach the fig
Given from the figure, ∠1 = ∠3 are the vertically opposite angles Therefore, ∠3 = 65° Here, ∠1 + ∠2 = 180° are the linear pair [The two adjacent angles are said to form a linear pair of angles if their non–common arms are two opposite rays and sum of the angle is 180°] Therefore, ∠2 = 180° – 65° = 115° ∠2 = ∠4 are the vertically opposite angles [from the figure] Therefore, ∠2 = ∠4 = 115° And ∠3 = 65°Read more on Sarthaks.com - https://www.sarthaks.com/686455/in-fig-it-being-given-that-1-65-find-all-other-angles
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