Question

in the given figure 11.45 and equilateral triangle EAB surmount the square ABCD find the value of x and y​

Answer 1

Answer:

REF.Image

△BEC is an equilateral △le

⇒BE=EC=BC

But BC=CD(ABCD is a square)

⇒EC=CD⇒∠CED=∠CDE

In △ECD,∠CED+∠CDE+90+60=180

⇒2∠CED=30⇒∠CED=15

∘

∠BEC=60

∘

⇒x=60−15=45

Answer 2

Answer:

x = 45 degrees

y = 15 degrees

Step-by-step explanation:

In triangle EBC,

Angle EBC = 90+60 = 150 degrees

and , EB = BC

So, angle BEC = angle BCE

and , angle BEC + angle BCE + angle EBC = 180 degrees

(Sum of interior angles of a triangle = 180 degrees)

so, 2 x angle BCE = 180 - 150 = 30 degrees

( as, angle BEC = angle BCE)

 So, angle BCE ( y )= 30/2 = 15 degrees

Now, angle x = 60 degrees - angle BEC

                     = 60  - 15 = 45 degrees.