Question

In the given figure 6.111, triangleABC, AngleB > AngleC. If AM is the bisector of AngleBAC and AN is the perpendicular bisector of BC.
Prove that AngleMAN = Half (angleB - angleC)

Answer 1

Answer:

the given figure 6.111, triangleABC, AngleB > AngleC. If AM is the bisector of AngleBAC and AN is the perpendicular bisector of BC.

Prove that AngleMAN = Half (angleB - angleC)

hope it helps