In the given figure 6, AOB is a diameter and ABCD is a cyclic quadrilateral. If, ADC = 120°,
Then. BAC =?
Answers
Answered by
66
Answer:
ABCD is a cyclic quadrilateral.
∴ ∠ ADC + ∠ ABC = 180°
∴ 120 + ∠ ABC = 180°
∴ ∠ABC = 60°
But ∠ ACB = 90° ................... (Angle in semicircle)
In Δ ABC,
∠ BAC + ∠ ACB + ∠ ABC = 180°
∴ ∠ BAC + 90°+ 60° = 180°
∴ ∠ BAC + 150° = 180°
∴ ∠ BAC = 180°- 150°
∴ ∠ BAC = 30°
hope this helps you
xxxXRosiXxxx:
☺☺☺
Answered by
71
Answer:
Answer:
ABCD is a cyclic quadrilateral.
∴ ∠ ADC + ∠ ABC = 180°
∴ 120 + ∠ ABC = 180°
∴ ∠ABC = 60°
But ∠ ACB = 90° ................... (Angle in semicircle)
In Δ ABC,
∠ BAC + ∠ ACB + ∠ ABC = 180°
∴ ∠ BAC + 90°+ 60° = 180°
∴ ∠ BAC + 150° = 180°
∴ ∠ BAC = 180°- 150°
∴ ∠ BAC = 30°
hope this helps you
Mai kyu block krunga tumhe
Us hacker ne sbko block kr diya (╥﹏╥)
kis hacker ne
naam bolo
sayyyyyyyyyyyy
Are mujhe kya pta subha subha uth ke dekha dikha rha hai u have been logged out
passss and email address bhi change kr diya kisine
maine tumhe kal raat ko may be 1:00 ko black dp deekha maine socha ki tum sad mai ho essliye tumne black dp lagaya phir maine pucha kya hua phir kisine block kardhi
oyeeeeeeeee
oyeeeeeeeeeeeeeeeee
Similar questions