Question

In the given figure ∠A= (3x+2)0, ∠B=(x-3)0, ∠ACD=1270. Value of ∠A=………………….

Answer 1

Step-by-step explanation:

Angle ACD and ACB lie in a straight line.

So ACD+ACB=180°

ACB=180-ACD

ACB=180-127

ACB=53°

In a triangle the sum of all angles is 180°

So A+B+ACB=180

(3x+2)°+(x-3)°+53°=180°

4x-1+53=180°

4x=180-52=128

x=32°

Angle A=3x+2=3(32)+2=98°