Question

 In the given figure, ∠A = 45° , BD = 12cm, BC = 9cm and ∠ACD = ∠CBD = 90° . Find CD and AD

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Answer 1

Answer:

Question 1:

A chord of length 16 cm is drawn in a circle of radius 10 cm. Find the distance of the chord from the centre of the circle.

ANSWER:

Let AB be the chord of the given circle with centre O and a radius of 10 cm.

Then AB =16 cm and OB = 10 cm

From O, draw OM perpendicular to AB.

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ BM = (162) cm=8 cm

In the right ΔOMB, we have:

OB2 = OM2 + MB2 (Pythagoras theorem)

⇒ 102 = OM2 + 82

⇒ 100 = OM2 + 64

⇒ OM2 = (100 - 64) = 36

⇒ OM=36−−√ cm=6 cm

Hence, the distance of the chord from the centre is 6 cm.

Answer 2

Answer:

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Step-by-step explanation:

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