In the given figure, A and B are two points on sides PQ and PR of ∆PQR such that RA ⊥ PQ, QB ⊥ PR and AQ = BR. Prove that AR = BQ. plz answer as fast as possible
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Step-by-step explanation:
given AQ=BR
now we know RA prpndclr to PQ and QB to PR
hence PA= PB
IN trianles PBQand PAR
ANGLE P is common
PA =PB
angle PAR =PBQ. Right angles
therefore both triangles are congruent
by cpct
AR =BQ
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thank you for giving answer thank you so much
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