In the given figure, A, B and C are three points on a circle with centre O such that ∠BOC = 30° and ∠AOB = 60°. If D is a point on the circle other than the arc ABC, find ∠ADC.
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First add Angle AOB and Angle BOC which is subtended by arc ABC. So Angle AOC is 90⁰ . The theorem of circle = the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle. So Angle AOC is double of Angle
ADC =90⁰=2ADC
ADC= 90⁰/2
ADC=45⁰
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Step-by-step explanation:
ADC=45*
i hope it's helped you
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