In the given figure A, B, C, D are Concyclic. If angle ACB =30 and angle BDC= 35
then find
(1) angle ADC
(2)angle ABC
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Answered by
71
Sum of opposite angles of a cyclic quadrilateral = 180°
In cyclic quadrilateral ABCD:
⇒∠BAD + ∠ADC=180°
⇒50° + ∠ADC=180°
⇒∠ADC=180°
⇒ ∠ADC+∠CDE=180°
(Sum of angles on a straight line = 180°)
⇒ 130° + ∠CDE = 180°
⇒ ∠CDE = x = 50°
Answered by
1
Answer:
Sum of opposite angles of a cyclic
quadrilateral = 180°
In cyclic quadrilateral ABCD:
→ <BAD + ZADC=180°
→ 50° + ZADC=180°
⇒ ZADC=180°
→ ZADC+2CDE=180°
(Sum of angles on a straight line = 180°)
→ 130° + LCDE = 180°
→ LCDE = x = 50°
Hope it helps you
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