Question

In the given figure A B C D is a cyclic quadrilateral and O is the centre of the circle . If angle BOD=160* find BPD ??
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Answer 1

Answer:BOD = 160*

so BAD = 160/2 = 80*

since ABCD is a cyclic quad. opp angles are supplementry

so BCD = 180-80 = 100*

therefore, BPD = 100* (since angle on the same segment are equal)

Step-by-step explanation: