Question

In the given figure A, B, C is a triangle D is the midpoint of BC. AD is produced to E. BM and CN are the two perpendicular dropped from B and C respectively on AE.
Prove that:
1. ∆BMD =∆ CNO
2.BM = CN
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Answer 1

Hope u got the correct one!!!!!

Answer 2

$\bigtriangleup BMD \cong \bigtriangleup CND$

BM = CN (by cpct)

hence proved

Step-by-step explanation:

here , in triangle BMD and triangle CND

BD = CD ( D is the mid point )

$\angle BMD = \angle CND = 90^\circ\\\angle BDM = \angle CDN$

(vertical opposite angles )

therefore by AAS congruency rule

$\bigtriangleup BMD \cong \bigtriangleup CND$

2. BM = CN (by cpct)

hence proved

#Learn more:

In a triangle ABC, BM and CN are perpendiculars from B and C respectively on any line passing through A. If L is the mid-point of BC, then prove that ML = NL.

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