Question

In the given figure,A b=x
BC=z
AC=y
Find the value of :.
sin 2 A + cos2 A =​

Answer 1

Step-by-step explanation:

so here is a ABC in which we have an angle Q

so now its sides = AB = x (hypoteneus)

= BC = z ( perpendicular)

= AC = y (base)

so now sinQ = z/x

and cosQ = y/x

now sin^2Q = z^2 / x^2

and cos^2 Q = y^2 / x^2

their sum will be

sin^2Q + cos^2 Q = (z^2 / x^2) + (y^2/x^2)

= (z^2 + y^2) / x^2

[now according to the pythogoras theo.

perpendicular ^2 + base ^2 = hypoteneus ^2]

so now = z^2 + y ^2 = x^2

according to that

sin^2 Q + cos ^2Q = x^2 /x^2 = 1

sin^2 Q + cos ^2 Q = 1 answer

and this brings us to our proprty that

sin^2Q + cos^2 Q = 1

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