History, asked by nancy359, 2 days ago

In the given figure, a circle is touching a semi-circle at C and its diameter AB at 0. If AB = 28 cm, what is the radius of the inner circle ? ​

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Answered by suraj8650suman
8

ab = 28

ob = oa = 14

oc = 14.

divide oc =14/2,radius of inner circle is 7

Answered by Usernameeeeeeee
3

Answer:

AB = 28cm

AO = Half of AB,

= 28/2 = 14cm

ie,

AO = OB = 14cm

Then radius r = 14/2

=7cm

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